Homework Assignment 3

3.2

Which of the following lists of subsets of the set MATH form topologies.

- MATH MATH MATH - Yes

- MATH MATH MATH - No MATH MATH not in the list.

- MATH MATH MATH MATH Yes

-MATH MATH MATH MATH No , closed under union and intersection and $\QTR{Large}{S\ }$is in the list, but MATH is not.

3.4

Prove that a function MATH is continuous if and only if the inverse image of every closed set is closed.

Proof:

We use the following equations from the Boolean algebra of sets.

Suppose the inverse image of every closed set is closed. Let $\QTR{Large}{U}$ be an open set and $\QTR{Large}{U=T-A}$

Then $\QTR{Large}{A}$ is closed and so MATH is closed hence MATHis open.

Suppose that $\QTR{Large}{f}$ is continuous and $\QTR{Large}{A}$ is closed then MATHis open since $\QTR{Large}{T-A}$ is open

but then MATH is closed.

3.8

Let MATH be the floor function. MATHforMATH

Is $\QTR{Large}{f}$ continuous?

Answer:

No because the supspace topology on MATH is descrete so points are open sets but MATH

not an open set.

3.8

Let $\QTR{Large}{T}$ be a set and $\QTR{Large}{B}$ a collection of subsets closed under finite intersection, then $\QTR{Large}{U(B),}$ the set of arbitrary unions of sets of $\QTR{Large}{B}$ form a topology.on $\QTR{Large}{T}$ [ Added : $\QTR{Large}{T}$ and MATH are in $\QTR{Large}{B}$]

Proof:

Again, the solution amounts to recalling some properties of Boolean Algebras. In this case

We are given that $\QTR{Large}{T}$ and MATH are in $\QTR{Large}{U(B)}$. We are also given that arbitrary unions of sets of $\QTR{Large}{U(B)}$ is in $\QTR{Large}{U(B)}$. This is because a union of unions of sets in $\QTR{Large}{U(B)}$ is a union of sets. That a finit intersection of sets of $\QTR{Large}{U(B)}$ is in $\QTR{Large}{U(B)}$ is because an intersection of unions of sets in $\QTR{Large}{U(B)}$ is a union of intersections of sets.