Fix a Metric Space
and a point
Given
0
we define the open ball of radius
around
We say
is open if for any
there exist an
0
such that
The set of open sets is called the Topology defined by the Metric.
In a Metric Space
and
(the empty set) is open
Let
be an arbitrary set of open sets, then
is
also open.
Let
be
a finite set of open sets, then
is
also open.
1. and 2. follow directly from the definitions, however if you haven't been through this material you should write down the details.
3. makes use of the observation that if
then
.
Choose
. Let
. We have
for all
hence
.
18.2.1 Exercise: Show that
is open for any
0.
Solution:
For every
. We need to find some
0
such that
Let
and
For
every
. We have
.
Thus
since this is true for any
we have
Given Metric Spaces
,
and a function
.
We say that
is continuous a point
if given any
0
there is a
0
such that
.
We say that
is continuous if it is continuous at every point.
Exercise: Convince yourself that for
this is just the usual
definition.
Given Metric Spaces
,
,a function
is continuous if and only for every open set
is open in
Proof:
Assignment: To be turned in one week from today.
Solution:
Suppose for every open set
we know that
is open in
Suppose we are given
0
and
.
We need to find
0
such that
.
But by 18.2.1 we know that
is open. Hence
is open. Hence we can find
0
such that
. Or, equivalently,
Suppose
is continuous and
is open we need to show that
is open in
Suppose
we are given
0
and
such that
Since
is continuous, we can find
0
such that
Thus
Suppose we have two metrics
and
defined
on
that produce the same Topology (open sets). Then a function
is continuous with respect to the metric
if and only if it is continuous with respect to the metric
Exercise: State and prove the corresponding
appropriate result for
Suppose we have three Metric Spaces
,
, and
suppose
and
are continuous, then so is
Proof:
Let
be open. Since
is continuous so is
is open in
and since
is continuous
so is
Given Metric Spaces
,
we use the notation
,
to represent the set of continuous functions from
to
Let
be a metric space and
be a continuous function from
to
, then
,
,
where, as in 0.1,
Let
be a metric space and
be a continuous function from
to
,
then
,
,
where
Proof: Immediate from 18.5
Returning to 17.3 The Circle,
we want to show that the three Metrics
produce the same set of continuous functions.
Assignment: (To be turned in one week from today) We could simply use 18.4 (do this!)
Solution:
We need to show that
is open with respect to
iff it is open with respect to
iff
it is open with respect to
To accomplish this, it suffices to show that if we are given
and
0
we can find, in sequence
0
,
0
and
0
such that
One note: there is no loss of generality in assuming that the
or
we work with for the next computation are smaller than the one we initially
are given, or compute.
Beginning with a simple case, let
Suppose
we know that
then we know
So
.
The hardest calculations involve
. Given
0
, I need find
0
In computing
we make use of the inequality
for small positive values of
.
Let
then
0
0
and
0
for small
Now let
. Suppose
we have
or
The computation of
follows in a similar fashion using the observation that
for
0.
Let
and assume that
,
we have
but it will be useful in the sequel if we go about it in a slightly different way.
The identity map
is continuous with respect to any pair of the above Metrics.
Proof:
Using
to denote the identity map when considered as a map between specific Metric
spaces, it is sufficient to show
are continuous since for example,
is continuous by 18.5. Since all three arguments are
similar we give the details of 1. Choose
0
and
.
Let
. Suppose
.
we have
For
large radii points can be far apart in distance yet close in terms of angle.
Let
be a map of sets. suppose
is equipped with a Metric
.
Then if
is continuous with respect to any of the three metrics
is continuous with respect to the other two.
Proof:
Suppose
,
As a set map
on the other hand, by 18.7
is continuous for